60=5y^2-0

Solution for 60=5y^2-0 equation:

60=5y^2-0

We move all terms to the left:

60-(5y^2-0)=0

We get rid of parentheses

-5y^2+0+60=0

We add all the numbers together, and all the variables

-5y^2+60=0

a = -5; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-5)·60
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*-5}=\frac{0-20\sqrt{3}}{-10}
=-\frac{20\sqrt{3}}{-10}
=-\frac{2\sqrt{3}}{-1}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*-5}=\frac{0+20\sqrt{3}}{-10}
=\frac{20\sqrt{3}}{-10}
=\frac{2\sqrt{3}}{-1}
$